1879 Rhode Island gubernatorial election
Appearance
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County results Zandt: 50–60% 60–70% 70–80% 80–90% | |||||||||||||||||
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Elections in Rhode Island |
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The 1879 Rhode Island gubernatorial election was held on April 2, 1879. Incumbent Republican Charles C. Van Zandt defeated Democratic nominee Thomas W. Segar with 62.09% of the vote.
General election
[edit]Candidates
[edit]Major party candidates
- Charles C. Van Zandt, Republican
- Thomas W. Segar, Democratic
Other candidates
- Samuel Hill, Independent
Results
[edit]Party | Candidate | Votes | % | ±% | |
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Republican | Charles C. Van Zandt (incumbent) | 9,717 | 62.09% | ||
Democratic | Thomas W. Segar | 5,506 | 35.18% | ||
Greenback | Samuel Hill | 318 | 2.03% | ||
Majority | 4,211 | ||||
Turnout | |||||
Republican hold | Swing |
References
[edit]- ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved November 1, 2020.